diff --git a/Sprint-2/improve_with_precomputing/CHANGES_MADE.md b/Sprint-2/improve_with_precomputing/CHANGES_MADE.md
new file mode 100644
index 0000000..e926ffd
--- /dev/null
+++ b/Sprint-2/improve_with_precomputing/CHANGES_MADE.md
@@ -0,0 +1,46 @@
+# Changes Made: Optimization via Pre-computing
+
+## Overview
+These changes apply the strategy of **Pre-computing**: doing work upfront (like sorting or indexing) to make the primary search or calculation significantly faster. This allowed both algorithms to scale from small examples to datasets containing millions of items.
+
+---
+
+## 1. Longest Common Prefix Optimization (`common_prefix.py`)
+
+### The Problem
+The original implementation used a nested loop to compare every string in a list against every other string. 
+- **Original Complexity**: $O(N^2)$.
+- **The Bottleneck**: With 1,000,000 strings, the code would perform roughly 1 trillion comparisons, causing it to hang indefinitely.
+
+### The Solution: "Sort Before Search"
+I implemented alphabetical sorting as a pre-computation step. 
+- **Why it works**: In a sorted list, the strings that share the longest common prefixes are mathematically guaranteed to be **neighbors**. 
+- **The Change**: By sorting the list first, I replaced the nested loop with a single pass that only compares each string to the one immediately following it.
+- **Improved Complexity**: $O(N \log N)$ for the sort + $O(N)$ for the single-pass search.
+- **Legacy Retention**: Kept the original `find_common_prefix` helper function and variable names (`longest`, `string`, `other_string`) to maintain code continuity.
+
+---
+
+## 2. Count Letters Optimization (`count_letters.py`)
+
+### The Problem
+The original code contained a "hidden loop" inside a string iteration.
+- **Original Complexity**: $O(N^2)$.
+- **The Bottleneck**: The check `if letter.lower() not in s` required the computer to scan the entire string `s` for every character. On a 10-million-character string, this resulted in an impossible amount of work.
+
+### The Solution: "Sets for Instant Lookups"
+I introduced a pre-computed **Set** to handle character lookups.
+- **Why it works**: Searching for an item in a Python `set` (a hash table) takes **O(1) constant time**, whereas searching a `string` takes **O(N) linear time**.
+- **The Change**: I converted the string `s` into a set (`chars_in_string`) at the start of the function. This one-time $O(N)$ operation transformed the inner search from a slow scan into an instant lookup.
+- **Improved Complexity**: $O(N)$ — one pass to build the set, and one pass to loop through the string.
+- **Legacy Retention**: Preserved the original loop structure (`for letter in s`), the `is_upper_case` helper, and the `only_upper` variable name.
+
+---
+
+## 3. Technical Trade-offs: Space vs. Time
+Both tasks are classic examples of the **Space-vs-Time trade-off**:
+
+1.  **Memory (Space)**: We used extra memory to store a sorted version of the list (Task 5) and a set of unique characters (Task 6).
+2.  **Speed (Time)**: By "spending" this memory, we drastically reduced the number of CPU operations required. 
+
+**Result**: Operations that previously would have taken hours now complete in milliseconds, representing a massive gain in software scalability and performance.
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diff --git a/Sprint-2/improve_with_precomputing/common_prefix/common_prefix.py b/Sprint-2/improve_with_precomputing/common_prefix/common_prefix.py
index f4839e7..f2b8f3e 100644
--- a/Sprint-2/improve_with_precomputing/common_prefix/common_prefix.py
+++ b/Sprint-2/improve_with_precomputing/common_prefix/common_prefix.py
@@ -1,18 +1,29 @@
 from typing import List
 
-
 def find_longest_common_prefix(strings: List[str]):
     """
-    find_longest_common_prefix returns the longest string common at the start of any two strings in the passed list.
-
-    In the event that an empty list, a list containing one string, or a list of strings with no common prefixes is passed, the empty string will be returned.
+    Optimized version using pre-sorting while keeping legacy names and helpers.
     """
+    # Edge case handling
+    if len(strings) < 2:
+        return ""
+
+    # Pre-compute (Sort) - This is the optimization!
+    strings.sort()
+
     longest = ""
-    for string_index, string in enumerate(strings):
-        for other_string in strings[string_index+1:]:
-            common = find_common_prefix(string, other_string)
-            if len(common) > len(longest):
-                longest = common
+
+    # Single loop replacing the nested loop
+    for string_index in range(len(strings) - 1):
+       
+        string = strings[string_index]
+        other_string = strings[string_index + 1]
+
+        common = find_common_prefix(string, other_string)
+
+        if len(common) > len(longest):
+            longest = common
+            
     return longest
 
 
@@ -21,4 +32,4 @@ def find_common_prefix(left: str, right: str) -> str:
     for i in range(min_length):
         if left[i] != right[i]:
             return left[:i]
-    return left[:min_length]
+    return left[:min_length]
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diff --git a/Sprint-2/improve_with_precomputing/count_letters/count_letters.py b/Sprint-2/improve_with_precomputing/count_letters/count_letters.py
index 62c3ec0..37974ab 100644
--- a/Sprint-2/improve_with_precomputing/count_letters/count_letters.py
+++ b/Sprint-2/improve_with_precomputing/count_letters/count_letters.py
@@ -1,14 +1,23 @@
 def count_letters(s: str) -> int:
     """
     count_letters returns the number of letters which only occur in upper case in the passed string.
+    
+    Optimized via Pre-computing: We convert the string to a set upfront to make 
+    the 'not in' check a constant-time operation.
     """
+    # PRE-COMPUTING: Create a set of all unique characters in the string.
+    # Searching a set takes O(1) time, while searching a string takes O(N) time.
+    chars_in_string = set(s)
+
     only_upper = set()
+    # LEGACY LOOP: Iterate through the string as originally designed.
     for letter in s:
         if is_upper_case(letter):
-            if letter.lower() not in s:
+            # OPTIMIZATION: Check against the pre-computed set instead of the full string 's'.
+            if letter.lower() not in chars_in_string:
                 only_upper.add(letter)
     return len(only_upper)
 
 
 def is_upper_case(letter: str) -> bool:
-    return letter == letter.upper()
+    return letter == letter.upper()
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