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Week 13 Kth Smallest Element in a BST Solution
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# Definition for a binary tree node.
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# class TreeNode:
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# def __init__(self, val=0, left=None, right=None):
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# self.val = val
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# self.left = left
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# self.right = right
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class Solution:
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# Time Complexity O(N)
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def kthSmallest(self, root: Optional[TreeNode], k: int) -> int:
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ans = []
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final = [0]
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def dfs(node):
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if not node:
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return
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dfs(node.left)
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ans.append(node.val)
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if len(ans) == k:
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final[0] = node.val
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if len(ans) < k:
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dfs(node.right)
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dfs(root)
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return final[0]
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