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| 1 | +/** |
| 2 | + * Definition for a binary tree node. |
| 3 | + * public class TreeNode { |
| 4 | + * int val; |
| 5 | + * TreeNode left; |
| 6 | + * TreeNode right; |
| 7 | + * TreeNode() {} |
| 8 | + * TreeNode(int val) { this.val = val; } |
| 9 | + * TreeNode(int val, TreeNode left, TreeNode right) { |
| 10 | + * this.val = val; |
| 11 | + * this.left = left; |
| 12 | + * this.right = right; |
| 13 | + * } |
| 14 | + * } |
| 15 | + */ |
| 16 | +class Solution { |
| 17 | + boolean answer = true; |
| 18 | + Deque<Integer> leftStack = new ArrayDeque<>(); |
| 19 | + Deque<Integer> rightStack = new ArrayDeque<>(); |
| 20 | + |
| 21 | + public boolean isValidBST(TreeNode root) { |
| 22 | + rightStack.push(root.val); |
| 23 | + dfs(root.left, root, "left"); |
| 24 | + rightStack.pop(); |
| 25 | + |
| 26 | + leftStack.push(root.val); |
| 27 | + dfs(root.right, root, "right"); |
| 28 | + leftStack.pop(); |
| 29 | + |
| 30 | + return answer; |
| 31 | + } |
| 32 | + |
| 33 | + public void dfs(TreeNode node, TreeNode parent, String direction) { |
| 34 | + if (node == null) return; |
| 35 | + |
| 36 | + if (direction.equals("left") && node.val >= parent.val){ |
| 37 | + answer = false; |
| 38 | + } |
| 39 | + if (direction.equals("right") && node.val <= parent.val){ |
| 40 | + answer = false; |
| 41 | + } |
| 42 | + if (!leftStack.isEmpty() && node.val <= leftStack.peek()) { |
| 43 | + answer = false; |
| 44 | + } |
| 45 | + if (!rightStack.isEmpty() && node.val >= rightStack.peek()) { |
| 46 | + answer = false; |
| 47 | + } |
| 48 | + |
| 49 | + rightStack.push(node.val); |
| 50 | + dfs(node.left, node, "left"); |
| 51 | + rightStack.pop(); |
| 52 | + |
| 53 | + leftStack.push(node.val); |
| 54 | + dfs(node.right, node, "right"); |
| 55 | + leftStack.pop(); |
| 56 | + } |
| 57 | +} |
| 58 | + |
| 59 | + |
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